1/8x^3-1/2x=6

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Solution for 1/8x^3-1/2x=6 equation:


x in (-oo:+oo)

(1/8)*x^3-((1/2)*x) = 6 // - 6

(1/8)*x^3-((1/2)*x)-6 = 0

(1/8)*x^3+(-1/2)*x-6 = 0

(1/8)*x^3+(-1/2)*x-6 = 0

(1/8)*x^3+(-1/2)*x-6 = 0 // * 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 16, -16, 24, -24, 48, -48 }

1

x = 1

x^3-4*x-48 = -51

1

-1

x = -1

x^3-4*x-48 = -45

-1

2

x = 2

x^3-4*x-48 = -48

2

-2

x = -2

x^3-4*x-48 = -48

-2

3

x = 3

x^3-4*x-48 = -33

3

-3

x = -3

x^3-4*x-48 = -63

-3

4

x = 4

x^3-4*x-48 = 0

4

x-4

x^2+4*x+12

x^3-4*x-48

x-4

4*x^2-x^3

4*x^2-4*x-48

16*x-4*x^2

12*x-48

48-12*x

0

x^2+4*x+12 = 0

DELTA = 4^2-(1*4*12)

DELTA = -32

DELTA < 0

x in { 4}

x = 4

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